Step 19 of Meredith's proof of Lukasiewicz axioms from his sole axiom.
(Contributed by NM, 14-Dec-2002.) (Proof modification is discouraged.)
(New usage is discouraged.)
\( \vdash (\varphi \rightarrow \varphi \rightarrow \psi) \rightarrow \theta \rightarrow \varphi \rightarrow \psi \)
\( \vdash ((((\varphi \rightarrow \varphi) \rightarrow \neg \varphi \rightarrow \neg \varphi) \rightarrow \varphi) \rightarrow \varphi) \rightarrow (\varphi \rightarrow \varphi) \rightarrow \varphi \rightarrow \varphi \)
\( \vdash (((((\varphi \rightarrow \psi) \rightarrow \varphi) \rightarrow \neg \varphi \rightarrow \neg \theta) \rightarrow \varphi) \rightarrow \varphi) \rightarrow (\varphi \rightarrow \varphi \rightarrow \psi) \rightarrow \theta \rightarrow \varphi \rightarrow \psi \)
\( \vdash ((((((\varphi \rightarrow \psi) \rightarrow \varphi) \rightarrow \neg \varphi \rightarrow \neg \theta) \rightarrow \varphi) \rightarrow \varphi) \rightarrow (\varphi \rightarrow \varphi \rightarrow \psi) \rightarrow \theta \rightarrow \varphi \rightarrow \psi) \rightarrow (((((\varphi \rightarrow \varphi) \rightarrow \neg \varphi \rightarrow \neg \varphi) \rightarrow \varphi) \rightarrow \varphi) \rightarrow (\varphi \rightarrow \varphi) \rightarrow \varphi \rightarrow \varphi) \rightarrow (\varphi \rightarrow \varphi \rightarrow \psi) \rightarrow \theta \rightarrow \varphi \rightarrow \psi \)
\( \vdash (((((\varphi \rightarrow \varphi) \rightarrow \neg \varphi \rightarrow \neg \varphi) \rightarrow \varphi) \rightarrow \varphi) \rightarrow (\varphi \rightarrow \varphi) \rightarrow \varphi \rightarrow \varphi) \rightarrow (\varphi \rightarrow \varphi \rightarrow \psi) \rightarrow \theta \rightarrow \varphi \rightarrow \psi \)