Theorem
expcomd
Deduction form of
expcom
. (Contributed by Alan Sare, 22-Jul-2012.)
Hypothesis
expcomd.1
\( \vdash \varphi \rightarrow \psi \wedge \chi \rightarrow \theta \)
Conclusion
\( \vdash \varphi \rightarrow \chi \rightarrow \psi \rightarrow \theta \)
Proof
expcomd.1
expd
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com23
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