This tautology shows that xor is really exclusive. (Contributed by FL,
22-Nov-2010.)
\( \vdash \varphi \veebar \psi \leftrightarrow \varphi \wedge \neg \psi \vee \neg \varphi \wedge \psi \)
\( \vdash \varphi \veebar \psi \leftrightarrow \neg (\varphi \leftrightarrow \psi) \)
\( \vdash \neg (\varphi \leftrightarrow \psi) \leftrightarrow \varphi \wedge \neg \psi \vee \psi \wedge \neg \varphi \)
\( \vdash \varphi \wedge \neg \psi \vee \psi \wedge \neg \varphi \leftrightarrow \varphi \wedge \neg \psi \vee \neg \varphi \wedge \psi \)