Deduction adding a biconditional to the left in an equivalence.
(Contributed by NM, 11-May-1993.) (Proof shortened by Wolf Lammen,
19-May-2013.)
\( \vdash \varphi \rightarrow (\theta \leftrightarrow \psi \leftrightarrow (\theta \leftrightarrow \chi)) \)
\( \vdash \varphi \rightarrow \theta \leftrightarrow \varphi \rightarrow \psi \leftrightarrow (\varphi \rightarrow \theta \leftrightarrow \varphi \rightarrow \chi) \)
\( \vdash \varphi \rightarrow (\theta \leftrightarrow \psi) \leftrightarrow (\varphi \rightarrow \theta \leftrightarrow \varphi \rightarrow \psi) \)
\( \vdash \varphi \rightarrow (\theta \leftrightarrow \chi) \leftrightarrow (\varphi \rightarrow \theta \leftrightarrow \varphi \rightarrow \chi) \)